Will take your calculations of moles as being correct.On that basis notice that, from the equations you have written, it would take 2moles of KI to one mole of the lead compound;and so you would need 2 moles of the iodide to react with one mole of the lead iodide.and so the the lead salt seems to be in excess.You've done a lot of work and I hope you get the benefit of it.
No comments:
Post a Comment